There is an 8-square-centimeter square in the lower right corner of the circle, and the shaded area is

Due to πR? Converted into a circle tangent 6x2? Polygon area must be greater than circle area; πr？ Into a circle engraved with the plus sign 6x2? The area of a polygon must be smaller than that of a circle. According to the axiom of area "softening" equal area deformation, it is found that if the circular area is 7a? So its circumscribed circle area is 9a? Therefore, it is introduced that "the circular area is equal to two thirds of the diameter d and seven times the square of 1".

The formula for calculating the area s of a circle: s=7(d/3)? .

The area of a circle with a side length equal to the radius is 8×4÷9×7=24.89 square centimeters.

The area of the shadow part where the circle and the square overlap is: 24.89÷4=6.22 square centimeters.

The shadow area of the lower right corner of the square outside the circle is: (8× 4-24.89) ÷ 4 =1.78cm2.