When I calculate the transformer, the impedance voltage actually accounts for 67%. How to modify the data to reduce the impedance voltage? thank you

Just kidding, this is a high impedance transformer.

First of all, it must be clear that you have not miscalculated, so I have the following suggestions.

1, the first is to reduce the number of turns, because the reactance is proportional to the square of the number of turns, and reducing the number of turns can greatly reduce the transformer impedance. But as the voltage per turn increases, the magnetic field density will also increase.

2. In order to ensure that the iron loss is not increased, only the magnetic field density is kept constant. Then increase the diameter of the iron core and reduce the magnetic field density. This will increase the diameter of the coil and reduce the height (reactance height), thus increasing the impedance, but the impact is much smaller than reducing the number of turns. What's next:

3. Change the specification of the electromagnetic wire to be thin and wide, reduce the width of the coil and increase the height of the coil. If it is a pancake coil, it is necessary to increase the number of cakes and reduce the coil width. That is, make the coil thinner. If it is a cylindrical coil, it is necessary to reduce the number of layers and increase the coil height.

4. It is very effective to change the impedance by changing the distance of the main air passage between high pressure and low pressure.

5. Changing the magnetic leakage area is also very effective.

6. Try this first, and then come to me for discussion if you have difficulties.