Solve the problem of chickens and rabbits in the same cage in the fourth grade of primary school

Title: There is a cage with many chickens and rabbits in it. Count. There are 14 heads and 38 legs. How many chickens and rabbits are there? Please answer in as many ways as possible.

Method 3: The coolest golden rooster independence method

Analysis: Let each chicken stand on one foot and each rabbit stand on two hind feet, then the total number of feet on the ground is only half of the original, that is, 19 feet. The chicken has the same number of feet as the rabbit, and the rabbit has twice as many feet. Therefore, if you subtract the number of heads from 19, the remaining number is 19- 14 = 5 rabbits and 14-5 = 9 chickens.

"Method 4: The funniest way to whistle"

Analysis: suppose that chickens and rabbits are trained by special forces and blow a whistle. They raise one foot and stand on 38- 14=24 legs. After another whistle, they raised another foot. At this time, the chicken was sitting on the ground, and the rabbit was still standing on two feet. At this time, there are still 24- 14= 10 legs standing, and these 10 legs are rabbits, so there are 10÷2=5 rabbits and 14-5=9 chickens. It's amazing that Bao Beier's foot lifting method in running men is wood! )

"Method 5: The most commonly used hypothetical method"

Analysis: If all chickens are chickens, they have 14×2=28 legs, which is 38-28= 10 less than the actual situation. Chickens turn into rabbits have two legs, 10÷2=5, so it takes five chickens to turn into rabbits, that is, five rabbits and 65438 chickens.

"Method 6: The most commonly used hypothetical method"

Analysis: It is assumed that all rabbits have 14×4=56 legs, which is 56-38= 18 more than the actual situation. When a rabbit becomes a drumstick, minus 2, 18÷2=9, so it takes 9 rabbits to become chickens, that is, 9 chickens and 65,438 rabbits.