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Joke zzox
Solution:
The tangent plane of the surface is xXo-2yYo+2zZo= 1.
Find the shortest distance, the tangent plane is parallel to the plane x+y+z=2.
That is XO/1=-2yo/1= 2zo/1.
That is Xo=-2Yo=2Zo.
That is 2 zzo+2yZo+2 zzo = 1.
That is 2Zo(x+y+z)= 1.
∴Zo≠0
∴x+y+z= 1/2Zo
The distance of ∴ is |2- 1/2Zo|
Let Zo=a
Then the point (2a, -a, a) is the tangent point and satisfies the curve equation.
(2a)? -2(-a)? +2(a)? = 1
The solution is a = 1/2.
∴ When a=- 1/2, that is, the point (-1, 1/2,-1/2) has the longest distance to the plane, and the longest distance is 3.
When a= 1/2, that is, the point (1,-1/2, 1/2) has the shortest distance to the plane, and the shortest distance is 1.
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