Help us analyze this circuit diagram! Tell me how it works. Have something to add!

When the switch is on the left, the battery charges the capacitor of 47u, and when the switch is in the position shown in the figure, the capacitor discharges the resistor of 10m. 1m and 200k are sampling resistors, which provide a reference source for the voltage division power supply of comparator 062, and this reference source is compared with the voltage of capacitive resistor; When the switch just rotates to the right, the capacitor voltage is basically equal to the power supply voltage, so the voltage at pin 3 of the comparator is higher than that at pin 2, so 90 1 3 of the output1is turned on, and the corresponding 90 15 is also turned on continuously. Because the capacitor 47u discharges the resistor of 10m, the voltage at pin 3 continues to decrease. When the voltage at pin 3 is equal to or less than the voltage at pin 2, the output level of the comparator is reversed, and the output is 0, which causes the two transistors to turn off and turn off.

I wonder if I can understand it?