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Why is R3 less electric power? draw

If R 1 is regarded as a part, and R2 and R3 are regarded as a part, then it can be considered that R 1 and (R2 R3) are connected in series, and the resistance of R3' s access circuit becomes smaller. According to the resistance ratio of each part in the series circuit, the voltage it bears becomes smaller, that is to say, the voltage borne by the (R2 R3) part becomes smaller, and the electric power with P = R3 becomes smaller.

Let's talk about the problem (which resistor consumes more power). It is considered that the (R2 R3) part of the resistor becomes smaller and the voltage it bears becomes smaller, so the voltage it bears in the E 1 part will become larger, P=UI, so the resistor that consumes more electric power is R 1.

If there is anything you don't understand, please ask. Thank you.