Prediction method of Fucai two-color ball

10 number protection method. In other words, if I randomly choose a blue ball and predict that I will be out of bounds at 10, then the highest success rate will reach 39% in the next 10 period. If a blue ball appears repeatedly in the middle, the out-of-bounds rate at a given position will drop to 37%. Even if another duplicate sign appears, there is a probability of 1 1%. If there are three duplicate numbers less than 10, the probability of occurrence will drop to 0.2%, and the bet will be given up soon. However, only 1 1% triplet appeared in 10. 1 betting method. That is to say, if there is no repetition, randomly select one of the nine balls that have been played, and the winning probability should be 37% ×1/9 = 4.1%; The probability of winning one of the remaining six balls is 16%× 1/7=2.3%, so it is suggested to choose the ball that has already been played. If there has been duplication, theoretically, if one of the eight balls is randomly selected from the nine balls that have been served, the probability of winning is 37% ×1/8 = 4.625%; If you choose one of the remaining eight balls, the winning probability is 39%× 1/8=4.875%. Because the probability is almost equal, it is suggested to choose the ball number for easy memory and unification. If two blue balls appear repeatedly in the first nine periods, one of the seven blue ball numbers issued in the first nine periods is randomly selected (assuming that each ball is repeated at most once), and the winning probability is11%×1/7 =1.6%; The winning probability of randomly selecting one of the remaining balls is 37%× 1/9=4. 1%. It is suggested to choose one of the remaining balls. If the blue ball played in the first nine periods is repeated three times, it can be 99.8% sure that the blue ball played the remaining balls in the next period. Then among the remaining 10 balls (assuming that each ball is repeated at most once), the winning probability of randomly selecting one ball is 10%. From the comparison of the two methods, it can be seen that the highest probability of 1 betting method is not as big as the lowest probability of winning 10 betting method. Therefore, I suggest to use 10 betting method and 1 betting method to bet on two-color ball. When three duplicate numbers are found in the first nine blue balls, choose the remaining blue balls decisively, and use the package number method if possible, otherwise use the 10 number protection method. The third betting method, which I personally summed up, is to kill the coldest one, and the coldest one should reach more than 50, so as to prepare for the 20 th issue. The probability of the 20 th issue should be 90%. I was in the two-color ball blue club, and I used this method in four successful periods. This method can also be derived from another method, that is, using the principle of balance, after the coldest ball comes out, it will definitely be repeated in the near future. For example, when the No.7 ball of the 2007072 blue ball served, I decided to call No.7 again, without any accident.