There are no math problems.

1。 Abe and ECF are similar triangles AB/BE = 5/2 = EC/CF.

2。 BC passes through the vertical line of P and K. Because the angle PCK=45 degrees, CK=PK=x, (3+x)/x=5/2.

X=2, AE=EP, and two triangles are congruent.

3。 Yes, the distance to point A is 2. Why am I just saying it briefly? It's hard to say details when typing. When you connect this point, you will find two triangular dams and EKP congruence. Through congruence, it can be proved that the two opposite sides of DM and PE are parallel and equal, and then the parallelogram.