It is known that the line segment AB=6, C and D are two points on AB, AC = DB = 1, and P is the moving point on the line segment CD, which are three equilateral points on the same side of AB.

The answer to this question is 2. You can establish a direct coordinate system with point C as the origin, and then set P(x, 0), where x ranges from 0 to 4. Then x is used to represent the coordinates of the G point, and the formula that the ordinate of the G point is constant and the abscissa is about x can be obtained. Then bring x = 4 and x = 0 into the abscissa of G point and subtract them to get the answer of 2. As I don't know much about painting, I will dictate my thoughts here. You can follow this line of thinking and get the correct answer soon. )