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t? =? s/v

As can be seen from the title, the angle of particle injection and ejection is 90, that is, 1/4 circle.

Namely:? s? =0.25*3. 14*r

r? =? mv/qB

= & gt? t? =? 0.25*3. 14*r/v? =0.25*3. 14*mv/qB? /v? =? 3. 14m/4qB

r? =? 3R/5+4R/5? =? 7R/5

As can be seen from the figure, O'acb is a square.

Ob=R=Oa

OO'=OO '

That is, o is on the diagonal O'c of the square.

So Of=Oe

Oecf is a square.

That is Oe=ec.

Oe=3R/5

Oa= R

= & gtEa = 4R/5 (Pythagorean theorem)

So r = O 'a = AC = AE+EC = AE+OE = 3r/5+4r/5 = 7r/5.

r? =? mv/qB? =? 7R/5? = & gt? v? =? 7qBR/5m