Second year mathematics in high school, using formulas to find coordinates

The following is the answer I stole from the Internet, but in my opinion this image is very easy to draw. First

draw 2|x| |y|=lamda, and then press Just translate the vector (3, 4), that is, first translate 3 units to the right, and then translate up four units.

Let’s talk about how to draw 2|x| |y|=lamda. It’s very easy. It is a figure that is symmetrical about both the x-axis and the y-axis.

So just draw the image of the first quadrant and then symmetry it to the other four quadrants. It is very simple

We translate the coordinate origin to (3, 4), then the original equation in the new coordinate system is 2|x| |y|=lamda

So we can first discuss y=-2x lamda (In the original coordinate system xgt; = 3, ygt; = 4; in the new coordinate system x, ygt; = 0 interval) image (shown as line segment BC in the figure below)

The coordinates of point B ( 3, 4 lamda) (under the old coordinate system), the BC slope is -2;

After we flip BC to the left, we get the y=-2|x| lamda (under the new coordinate system) image , and then fold it down to get the image of |y|=-2|x| lamda (under the new coordinate system), as shown in the figure below:

That is, the image above is the image in the original question , rhombus, and center coordinate (3, 4) BC slope -2, B coordinate (3, 4 lamda) (where lamdagt; = 0)