1)x-3y = 22) 1-y = 3x 3)x-2 = 2(y- 1)3x-2y = 12x-5y =-222(x-2)+(y-)

Solution: From the first equation: x=2+3y,

Bring in the second equation: 1-y=6+9y, and y=-2, so x =-4;

2) x-2=2(y- 1)，3x-2y= 1

Solution: From the first equation: x=2+2(y- 1),

Bring in the second equation: 3(2+2(y- 1))-2y= 1, that is, 6+6y-6-2y= 1, and get Y = 1/4 and X = 65438+.

3) 2x-5y=-22，2(x-2)+(y- 1)=5

J solution: From the first equation: 2x=-22+5y,

Bring in the second equation: -22+5y-4+(y- 1)=5, and get that 6y = 32, y = 16/3.

Then, 2x=-22+5* 16/3, x = 4；;