Jokes about Donkeys Eating Carrots

Wanting businessmen to sell the most is equivalent to letting horses eat the least, and wanting horses to eat the least is equivalent to walking the shortest distance.

No matter how many horses you carry, you eat 1 carrot every time you run 1 km, so try to leave the carrots on the horse, and the carrots will be the most left in the end; In order to transport a horse, it is necessary to fully load (65,438+0,000) on the horse at the beginning of each section, which requires that the number of carrots in each section must be an integer multiple of 65,438+0,000-3,000, with 65,438+0,000 carrots at a time, and 3,000 divided by 65,438.

Suppose the first stop is point A, and the horse has to go back and forth five times (the first time is 1000, go back; 1000 for the second time, go back; Third time 1000, don't go back. There is a problem with staged transportation-the horses have to eat when they go back, so the carrots they put down need fewer trips back)

The first integer multiple is 2000, which means that when all the carrots are transported to point A, the total number of carrots should be 2000. So where is point A to ensure that there are 2000 carrots left on the ground? Obviously, it is the place where I ate 1000 carrots five times, which is 1000/5=200 kilometers.

Suppose the second stop is point B, and 2000 carrots have to go back and forth from A to B three times. Similarly, point B should be located at a distance of 1000/3 = 333.3 kilometers.

Let the horse carry 1000 carrots from A to B, eat 333 carrots on the way, put down 334 carrots at point B, then turn back to point A and eat the remaining 333 carrots on the way. After arriving at point A, 65,438+0,000 rode off, and when passing through point B, it still contained 334. A total of 800 kilometers from A to the finish line, 800 horses were eaten, leaving 534 horses.